In this case Pr(A and B) = 5*(The integral from 0.4 to 0.6 of p^{2}) =

5*(p^{3}/3 from 0.4 to 0.6) =

(5/3)*(.216 - .064) =

19/75 =~ 0.2533333

Pr(B) = 5 * The integral from 0.4 to 0.6 of p = 0.5 .

Thus the answer is 38/75 =~ .5066667

Michael Shackleford, A.S.A.