Lets assume the chosen numbers are 1-2-3-4-5. Of the 19,575,738 ways to arrange the six drawn balls how many will fit the drawn numbers to make a winner? Take the ratio of that number of 19,575,738 and you have the probability.

There are 34 ways to draw the 6 numbers to match 1-2-3-4-5 (you must match all of the first 5, the bonus ball can be any of the remaining 34).

The number of ways to match four plus the bonus ball are 170 (the bonus ball can be any of the 5 you got right, and the last ball can be any of the remaining 34).

The number of ways to match four w/o the bonus ball are 5610 (5 different ways to arrange the 4 correct numbers * the 5th number can be any of the remaining 34 * the bonus ball can be any of the remaining 33).

Keep following the above logic for all possible winning combinations:

Ways Probability Expected Type of win to win of winning Payoff return -------------- ------ ----------- ------ -------- Pick 5 34 .0000017368 $50000 .0868 Pick 4 + BB 170 .0000086842 $600 .0052 Pick 4 w/o BB 5610 .0002865792 $400 .1146 Pick 3 + BB 11220 .0005731585 $30 .0172 Pick 3 w/o BB 179520 .0091705355 $15 .1376 Pick 2 + BB 179520 .0091705355 $2 .0183 Total 376074 .3798

**Note:** In all fairness to the state I should mention that you
can buy three tickets for the price of two, increasing the expected return to 56.97 cents
(but still a waste of money).

Michael Shackleford, A.S.A.