Let x be the number of non-tens you would have to remove to make this a fair bet. Since it pays 2:1 you should have a 1 in 3 chance of winning for it to be fair.
1/3 = 16/(52-x)
52-x = 48
Thus you would have to remove four non-tens from a single deck game to make this a fair bet.
Michael Shackleford, A.S.A.